Fix pylint formating
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@ -15,26 +15,27 @@ def checksum(file_path, blocksize=65536):
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:returns: str or None
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:returns: str or None
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"""
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"""
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hasher = hashlib.sha256()
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hasher = hashlib.sha256()
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with open(file_path, 'rb') as f:
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with open(file_path, 'rb') as file:
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buf = f.read(blocksize)
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buf = file.read(blocksize)
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while len(buf) > 0:
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while len(buf) > 0:
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hasher.update(buf)
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hasher.update(buf)
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buf = f.read(blocksize)
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buf = file.read(blocksize)
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return hasher.hexdigest()
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return hasher.hexdigest()
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return None
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return None
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def distance_between_two_points(lat1, lon1, lat2, lon2):
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def distance_between_two_points(lat1, lon1, lat2, lon2):
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# As threshold is quite small use simple math
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"""Return distance between two points"""
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# From http://stackoverflow.com/questions/15736995/how-can-i-quickly-estimate-the-distance-between-two-latitude-longitude-points # noqa
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# From http://stackoverflow.com/questions/15736995/how-can-i-quickly-estimate-the-distance-between-two-latitude-longitude-points # noqa
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# convert decimal degrees to radians
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# convert decimal degrees to radians
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lat1, lon1, lat2, lon2 = list(map(radians, [lat1, lon1, lat2, lon2]))
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lat1, lon1, lat2, lon2 = list(map(radians, [lat1, lon1, lat2, lon2]))
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r = 6371000 # radius of the earth in m
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rad = 6371000 # radius of the earth in m
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x = (lon2 - lon1) * cos(0.5 * (lat2 + lat1))
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x = (lon2 - lon1) * cos(0.5 * (lat2 + lat1))
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y = lat2 - lat1
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y = lat2 - lat1
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return r * sqrt(x * x + y * y)
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return rad * sqrt(x * x + y * y)
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def get_date_regex(user_regex=None):
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def get_date_regex(user_regex=None):
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