Fix pylint formating
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				@ -15,26 +15,27 @@ def checksum(file_path, blocksize=65536):
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    :returns: str or None
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					    :returns: str or None
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    """
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					    """
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    hasher = hashlib.sha256()
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					    hasher = hashlib.sha256()
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    with open(file_path, 'rb') as f:
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					    with open(file_path, 'rb') as file:
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        buf = f.read(blocksize)
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					        buf = file.read(blocksize)
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        while len(buf) > 0:
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					        while len(buf) > 0:
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            hasher.update(buf)
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					            hasher.update(buf)
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            buf = f.read(blocksize)
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					            buf = file.read(blocksize)
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        return hasher.hexdigest()
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					        return hasher.hexdigest()
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    return None
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					    return None
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def distance_between_two_points(lat1, lon1, lat2, lon2):
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					def distance_between_two_points(lat1, lon1, lat2, lon2):
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    # As threshold is quite small use simple math
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					    """Return distance between two points"""
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    # From http://stackoverflow.com/questions/15736995/how-can-i-quickly-estimate-the-distance-between-two-latitude-longitude-points  # noqa
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					    # From http://stackoverflow.com/questions/15736995/how-can-i-quickly-estimate-the-distance-between-two-latitude-longitude-points  # noqa
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    # convert decimal degrees to radians
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					    # convert decimal degrees to radians
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    lat1, lon1, lat2, lon2 = list(map(radians, [lat1, lon1, lat2, lon2]))
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					    lat1, lon1, lat2, lon2 = list(map(radians, [lat1, lon1, lat2, lon2]))
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    r = 6371000  # radius of the earth in m
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					    rad = 6371000  # radius of the earth in m
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    x = (lon2 - lon1) * cos(0.5 * (lat2 + lat1))
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					    x = (lon2 - lon1) * cos(0.5 * (lat2 + lat1))
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    y = lat2 - lat1
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					    y = lat2 - lat1
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    return r * sqrt(x * x + y * y)
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					    return rad * sqrt(x * x + y * y)
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def get_date_regex(user_regex=None):
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					def get_date_regex(user_regex=None):
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